-p^2=-9p+10

Solution for -p^2=-9p+10 equation:

-p^2=-9p+10

We move all terms to the left:

-p^2-(-9p+10)=0

We add all the numbers together, and all the variables

-1p^2-(-9p+10)=0

We get rid of parentheses

-1p^2+9p-10=0

a = -1; b = 9; c = -10;
Δ = b2-4ac
Δ = 92-4·(-1)·(-10)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{41}}{2*-1}=\frac{-9-\sqrt{41}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{41}}{2*-1}=\frac{-9+\sqrt{41}}{-2}
$